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所以 (1+0.05/n)^n*15 = (1 + 1/t)^(0.05t * 15) 當 n to inf => t to inf 所以加上lim會變成 lim_{t to inf} (1 + 1/t)^(0.05t * 15) = lim_{t to inf} ((1 + 1/t)^t)^(0.05 * 15) [ ps a^(xy) = (a^x)^y ] = e^(0.05 * 15)
參考資料 維基
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